- Sun Jan 11, 2009 1:19 am
#63269
(1) You can't use 25mil square pins for high power audio or DC
(2) You can't place inputs and outputs of an amp on adjacent pins
(3) You can't sum three amplifier modules into one as shown
Start by removing all the 25mil square pins and using
proper screw terminals rated to at least ten amps.
Something like this.
For a 50Watt amplifier module you will draw about 75Watts
from the DC supplies. At sixty volts you have to deliver
over one amp without local heating or high inductance,
both of which reduce reliability.
Keep the input signal and it's ground well away from
the output signal and power ground.
In the original design the three amplifier ICs were summed
with 200milliohm resistors, to a common load terminal. The
cables and connections to the summing point will need
to be much lower impedance (such as the fat trace/tracks
on the original board). If one (or two) go to a higher impedance
the remaining amplifier will be overloaded.
SpikedCola wrote:I made up a master board. It will attach to two slave boards (the other two amps). This look a bit better in terms of layout and trace size?Yes! Much better. Still a couple of issues to address:
(1) You can't use 25mil square pins for high power audio or DC
(2) You can't place inputs and outputs of an amp on adjacent pins
(3) You can't sum three amplifier modules into one as shown
Start by removing all the 25mil square pins and using
proper screw terminals rated to at least ten amps.
Something like this.
For a 50Watt amplifier module you will draw about 75Watts
from the DC supplies. At sixty volts you have to deliver
over one amp without local heating or high inductance,
both of which reduce reliability.
Keep the input signal and it's ground well away from
the output signal and power ground.
In the original design the three amplifier ICs were summed
with 200milliohm resistors, to a common load terminal. The
cables and connections to the summing point will need
to be much lower impedance (such as the fat trace/tracks
on the original board). If one (or two) go to a higher impedance
the remaining amplifier will be overloaded.