- Sun Feb 04, 2018 8:38 am
#198172
Hi folks,
I am looking into using the INA169 part to make a current measuring circuit... heres the link to the hook uo guide:
https://learn.sparkfun.com/tutorials/i ... 481576911
I was just wondering if I am calculating RS and RL properly?
As RS I need approximately (0-35ma) to 1 Amp measuring range.
And an RL that proportionally depicts a 0 to 3.0VDC as an output.
Here's the proposed formula:
IS =(VOUT x 1K ) / (RS x RL)
filling in the blanks:
1A = (3V x 1K) / (RS x 10K)
Solving for RS:
RS = 0.3 ohms at 1/2 watt, 2% precision
Is this correct???
Thank you all for your help
8V
I am looking into using the INA169 part to make a current measuring circuit... heres the link to the hook uo guide:
https://learn.sparkfun.com/tutorials/i ... 481576911
I was just wondering if I am calculating RS and RL properly?
As RS I need approximately (0-35ma) to 1 Amp measuring range.
And an RL that proportionally depicts a 0 to 3.0VDC as an output.
Here's the proposed formula:
IS =(VOUT x 1K ) / (RS x RL)
filling in the blanks:
1A = (3V x 1K) / (RS x 10K)
Solving for RS:
RS = 0.3 ohms at 1/2 watt, 2% precision
Is this correct???
Thank you all for your help
8V